Xe would certainly be your main atom, O is attached to it by a doublebond and your two Fs room attached it is in a solitary bond.
There would certainly be 3 Lone Pair (LP) electrons about F, 2 around O,and 2 roughly Xe. Why ? over there is no valance come this molecule for this reason youwant to satisfy the formal fee to it is in 0. Formal fee =(#electrons in ground state) - < (free electrons) - 1/2 (bondingelectrons)>.
Formal charge for F, would desire 0 so
0 = 7 - + 1/2 (2) > = 7 - (? +1) = 7 - ? - 1
? = 6, therefore 3 lone pairs around fluorines.
Formal fee for O, would want 0 so
0 = 6 - + 1/2 (4) >...
? = 4, thus 2 LP approximately oxygen
Formal charge for Xe, again we want it to be 0 so,
0 = 8 - + 1/2 (8)>.....
? = 4, because of this 2 LP around Xe.
Kind the a weird set up (since Xe does no follow the octectrule), yet it functions out =)
Wiki User∙ 10y ago
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