**Explanation**the range contain total 3 element.its subset room , 1, 2, 3, 1, 2, 2, 3, 3, 1, 1, 2, 3.so the output is 8..

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We know variety of subsets of collection of size n is

**2n**

**How walk this formula work?**For every element, we have two choices, us either choose it or execute not choose it. Therefore in full we have 2 * 2 * … (n times) options which is

**2n**Alternate explanation is :Number the subsets of dimension 0 = nC0Number the subsets of size 1 = nC1Number of subsets of size 2 = nC2………………..Total number of subsets = nC0 + nC1 + nC2 + …. + nCn =

**2n**Please refer amount of Binomial Coefficients because that details.

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